@@[ ‘޺ ]

‘æ68‰ñ‘S“ú–{’†ŠwZ’ÊM—¤ã‹£‹Z‹{è‘å‰ï

–{“ú‚Í2024”N5Œ3“ú(‹à) ‚Å‚·
s TEAM INF t
s ‹{è ’jq t
í–Ú׳İÄŞ‘gڰ݈ÊBib‘Iè–¼Šw”N‹L˜^...Q–—R
1”N’jq 100m—\‘I15333377²Ø» Õ·Ä
“ü² KãÄ
114"33
+3.2
.321
—\‘I15443381µ¶ÔÏ ¹²À
‰ªR Œj‘å
114"33
+3.2
.323
—\‘I16753384²¸ÎŞ À¸Ğ
ˆä‹v•Û‘ñŠC
114"58
+2.5
.573
1”N’jq 1500mŒˆŸ1113383ÀƸŞÁ б
’JŒû@ƒ~ƒA
15'24"09
.089
ŒˆŸ11393380ij¼Ş®³ Õ³¾²
“ŒŠ —Rª
16'04"11
.102
ŒˆŸ11723379À¹ÀŞ Õ³Ï
’|“c —I”n
15'30"87
.868
2”N’jq 100m—\‘I9463371Ƽ»ŞÜ ²ÁÙ
¼àV ˆê—®
213"87
-1.0
.867
‹¤’Ê’jq 200m—\‘I8443371Ƽ»ŞÜ ²ÁÙ
¼àV ˆê—®
226"75
+2.2
.750
—\‘I12163374ËÀ޶ ظ
“úûü@—˜—‰
228"53
+3.0
.524
—\‘I16353377²Ø» Õ·Ä
“ü² KãÄ
129"91
+3.3
.905
‹¤’Ê’jq 800m—\‘I8363382ºÏ· ¶İ½¹
¬–q ŠÂ‰î
12'56"48
.480
—\‘I873373ÄŞ² »Ä¼
“y‹ ‘u
2Œ‡ê
—\‘I81183378ÄØÏ٠ܶÅ
’¹ŠÛ ˜a—v
13'13"68
.677
‹¤’Ê’jq 1500mŒˆŸ1143369µ¼¶Ü Ğײ
‰Ÿì –¢—ˆ
3Œ‡ê
ŒˆŸ11943372ÂÀŞ Åµ·
’Óc ’¼÷
25'10"12
.111
ŒˆŸ2273375Ë×À Ø­³¾²
•½“c —®¹
24'58"48
.476
‹¤’Ê’jq 3000mŒˆŸ143379À¹ÀŞ Õ³Ï
’|“c —I”n
1Œ‡ê
ŒˆŸ1743372ÂÀŞ Åµ·
’Óc ’¼÷
211'15"54
.540
ŒˆŸ1223383ÀƸŞÁ б
’JŒû@ƒ~ƒA
1Œ‡ê
‹¤’Ê’jq 110mH—\‘I4323374ËÀ޶ ظ
“úûü@—˜—‰
220"67
+1.1
.665
—\‘I4463380ij¼Ş®³ Õ³¾²
“ŒŠ —Rª
123"22
+1.1
.212
‹¤’Ê’jq 4x100mRŒˆŸ33134701[‹{è]
1) ¬‹v•Û‘åŠM
2) ğˆä —²¬
3) ‰Ÿì –¢—ˆ
4) “ß{ ‰F’ˆ
5) •½“c —®¹

3
3
3
3
2
48"68
.673
’áŠw”N’jq 4x100mR—\‘I18634701[‹{è]
1) ¼àV ˆê—®
2) ˆä‹v•Û‘ñŠC
3) “ü² KãÄ
4) “úûü@—˜—‰
5) “y‹ ‘u
6) ‰ªR Œj‘å

2
1
1
2
2
1
53"83
.824
‹¤’Ê’jq ‘–•’µ—\‘I136173367»¶² Ø­³¾²
ğˆä —²¬
34m82
+1.7
—\‘I214113366º¸ÎŞ À²¶Ş
¬‹v•Û‘åŠM
35m13
+2.3
—\‘I231283375Ë×À Ø­³¾²
•½“c —®¹
23m97
+2.3
‹¤’Ê’jq –CŠÛ“Š(5.0kg)—\‘I1313373ÄŞ² »Ä¼
“y‹ ‘u
2Œ‡ê
—\‘I132183381µ¶ÔÏ ¹²À
‰ªR Œj‘å
16m65
—\‘I13643367»¶² Ø­³¾²
ğˆä —²¬
39m46
q
ŒˆŸ11293367»¶² Ø­³¾²
ğˆä —²¬
38m36
s ‹{è —q t
í–Ú׳İÄŞ‘gڰ݈ÊBib‘Iè–¼Šw”N‹L˜^...Q–—R
1”N—q 100m—\‘I16323370ÏÂÓÄ Ğ±
¼–{ [ˆ¤
114"53
+2.8
.529
—\‘I17313372ϵ Ø»
¼”ö —›Ñ
114"56
+1.5
.560
—\‘I17663371²Ü¾ ±¶Ø
ŠâûP éä»
115"60
+1.5
.592
2”N—q 100m—\‘I13513369ĞÈ ¹²Ä
•ô Œi‰¹
214"54
-1.5
.538
‹¤’Ê—q 200m—\‘I14413369ĞÈ ¹²Ä
•ô Œi‰¹
229"96
+3.3
.957
—\‘I14723370ÏÂÓÄ Ğ±
¼–{ [ˆ¤
130"20
+3.3
.192
‹¤’Ê—q 100mH—\‘I6743371²Ü¾ ±¶Ø
ŠâûP éä»
121"00
+2.9
.992
‹¤’Ê—q 4x100mRŒˆŸ23434701[‹{è]
1) ¼”ö —›Ñ
2) •ô Œi‰¹
3) ’†‘º ³ÙÙ
4) —Ñ —Ú—›¬
5) ¼–{ [ˆ¤
6) ŠâûP éä»

1
2
3
3
1
1
57"18
.176
‹¤’Ê—q ‘–•’µ—\‘I237283372ϵ Ø»
¼”ö —›Ñ
13m06
+2.2

–ß‚é