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s ‹v•ô ’jŽq t
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1”N’jŽq 100m—\‘I6434310ÎÝÀÞ ÊÙÄ
–{“c —zŸ
113"73
-0.1
.722
—\‘I11184311¶ØÔ ÊÙ·
‰¼‰® —z‹M
116"32
.314
—\‘I12334308Ï妆 ¼®³
¼ì §
113"99
+0.4
.990
2”N’jŽq 100m—\‘I9634301²Ü·Ø ËÅÄ
ŠâØ —zãÄ
212"91
+1.0
.910
—\‘I10464305¸Û·Þ ØËÄ
•–Ø —œm
213"47
+2.2
.465
—\‘I1344303ÌÙ²Á ËÛÄ
ŒÃŽs ‘åãÄ
2Œ‡ê
3”N’jŽq 100m—\‘I3644342ŶÀ¹ ¹Ý¼Ý
’†• Œ½L
311"76
+1.9
.757
—\‘I8774340ƼÀÞ Õ³Ï
¼“c —IáÁ
312"72
+0.1
.716
‹¤’Ê’jŽq 200m—\‘I4144342ŶÀ¹ ¹Ý¼Ý
’†• Œ½L
324"33
+0.3
.323
—\‘I5734331´Ä³ Ö¼·
]“¡ ”üàŠ
324"60
-0.2
.599
—\‘I10164340ƼÀÞ Õ³Ï
¼“c —IáÁ
326"17
+0.1
.169
‹¤’Ê’jŽq 400m—\‘I1734331´Ä³ Ö¼·
]“¡ ”üàŠ
354"53
.525q
—\‘I8654309À¶ÔÏ Ð·
ûüŽR ŽÀ’Î
21'16"59
.586
ŒˆŸ1464331´Ä³ Ö¼·
]“¡ ”üàŠ
354"67
.670
‹¤’Ê’jŽq 800m—\‘I2964346ƼÑ× À²Ö³
¼‘º ‘¾—z
32'08"88
.877
—\‘I57104304ÀÜ× ÊÙ·
•U —z‹P
32'37"17
.167
—\‘I61034307±×¶Ü ¹²ºÞ
rì ŒjŒá
12'22"29
.287
‹¤’Ê’jŽq 1500mŒˆŸ394306ÄÖ»ÞÄ À²¼
–L—¢ ‘׎u
2Œ‡ê
ŒˆŸ4914346ƼÑ× À²Ö³
¼‘º ‘¾—z
34'39"30
.293
ŒˆŸ5534338ÐÔÓÄ ¹Ý¼
‹{–{ ŒŽm
34'29"72
.716
‹¤’Ê’jŽq 3000mŒˆŸ120104302²½ÞÐ ÊÙ·
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211'21"83
.822
ŒˆŸ23154322¶ÜÉ Õ³Ä
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310'39"70
.697
ŒˆŸ318134338ÐÔÓÄ ¹Ý¼
‹{–{ ŒŽm
39'44"53
.525
‹¤’Ê’jŽq 4x100mRŒˆŸ66436601[‹v•ô]
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2) ’†• Œ½L
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4) ŒÃŽs ‘åãÄ
5) ‹{–{ ŒŽm
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3
3
3
2
3
3
47"30
.295
’áŠw”N’jŽq 4x100mR—\‘I38436601[‹v•ô]
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2) ¼ì §
3) –{“c —zŸ
4) ŠâØ —zãÄ
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6) rì ŒjŒá

2
1
1
2
2
1
52"32
.317
‹¤’Ê’jŽq ŽO’i’µŒˆŸ11994301²Ü·Ø ËÅÄ
ŠâØ —zãÄ
210m04
+0.5
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Ží–Ú׳ÝÄÞ‘gڰ݈ÊBib‘IŽè–¼Šw”N‹L˜^...QŽ–—R
1”N—Žq 100m—\‘I7144307ŶÞÉ Ø±Å
‰i–ì꣖¾“Þ
115"03
+0.5
.027
—\‘I8344309»Ä³ ØÉÊ
²“¡—œ”T‰Ø
115"41
+0.5
.401
—\‘I12224303¶ÜÉ ¶ÅÝ
ì–ì ‰Ø“í
115"27
+0.1
.262
1”N—Žq 800mŒˆŸ26124306²¼¶Ü غ
Îì 从q
13'12"92
.920
ŒˆŸ2854302¶ÒÀÞ ÐÕ
‹T“c S—D
12'56"70
.696
3”N—Žq 100m—\‘I1164315ÀŶ ÉÉÐ
“c’†ŠóX”ü
313"23
+1.0
.222q
—\‘I3124313Ȳ ÏÅÐ
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313"48
+1.0
.473
—\‘I9314311Ó¶ÞРϵ
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313"87
+1.3
.870
ŒˆŸ1254315ÀŶ ÉÉÐ
“c’†ŠóX”ü
313"23
-0.2
.230
‹¤’Ê—Žq 200m—\‘I2844315ÀŶ ÉÉÐ
“c’†ŠóX”ü
328"12
+0.2
.118
—\‘I10214311Ó¶ÞРϵ
–Ñã áÁ‰›
329"26
-0.1
.260
—\‘I15424301³´ÀÞ ±¶Ø
ã“c Žéä»
132"02
-0.5
.017
‹¤’Ê—Žq 800m—\‘I7114314·À¶ÞÜ ÕÅ
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22'48"09
.083
—\‘I7924304µÁ±² ÕÂÞ·
—Ž‡ —DŒŽ
12'49"58
.571
‹¤’Ê—Žq 1500mŒˆŸ12034314·À¶ÞÜ ÕÅ
–kì Œ‹ŒÈ
25'58"86
.856
‹¤’Ê—Žq 100mH—\‘I1334313Ȳ ÏÅÐ
ªˆä ˆ¤”ü
315"88
-0.3
.877q
ŒˆŸ1644313Ȳ ÏÅÐ
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315"83
+0.3
.827
‹¤’Ê—Žq 4x100mRŒˆŸ46136601[‹v•ô]
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2) “c’†ŠóX”ü
3) –Ñã áÁ‰›
4) ‰i–ì꣖¾“Þ
5) –kì Œ‹ŒÈ
6) ã“c Žéä»

3
3
3
1
2
1
53"58
.575
‹¤’Ê—Žq ‘–‚’µŒˆŸ1374303¶ÜÉ ¶ÅÝ
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1NM
‹¤’Ê—Žq –CŠÛ“Š(2.721kg)—\‘I140434308²· Îɶ
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14m01
—\‘I141404305ÎÝÀÞ ÁÊÙ
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14m70
‹¤’Ê—Žq ¼Þ¬ÍÞد¸½Û°(300g)ŒˆŸ1274309»Ä³ ØÉÊ
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129m18
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123m15
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1Œ‡ê

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